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53022111450401 is a prime number
BaseRepresentation
bin11000000111001001011000…
…00111100100010100100001
320221201212100010000121021102
430003210230013210110201
523422203241012403101
6304434004410004145
714111502231046202
oct1403445407442441
9227655303017242
1053022111450401
11159926076a2815
125b44059a16655
132377c6b1c7432
14d143d8db35a9
1561e36069986b
hex30392c1e4521

53022111450401 has 2 divisors, whose sum is σ = 53022111450402. Its totient is φ = 53022111450400.

The previous prime is 53022111450379. The next prime is 53022111450463. The reversal of 53022111450401 is 10405411122035.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38561317970176 + 14460793480225 = 6209776^2 + 3802735^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53022111450401 is a prime.

It is a super-2 number, since 2×530221114504012 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53022111450701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26511055725200 + 26511055725201.

It is an arithmetic number, because the mean of its divisors is an integer number (26511055725201).

Almost surely, 253022111450401 is an apocalyptic number.

It is an amenable number.

53022111450401 is a deficient number, since it is larger than the sum of its proper divisors (1).

53022111450401 is an equidigital number, since it uses as much as digits as its factorization.

53022111450401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 53022111450401 its reverse (10405411122035), we get a palindrome (63427522572436).

The spelling of 53022111450401 in words is "fifty-three trillion, twenty-two billion, one hundred eleven million, four hundred fifty thousand, four hundred one".