Base | Representation |
---|---|
bin | 1111011011100111111… |
… | …01010000001011100011 |
3 | 1212200121101112122122201 |
4 | 13231303331100023203 |
5 | 32141400430224212 |
6 | 1043325504114031 |
7 | 53210335105252 |
oct | 7556375201343 |
9 | 1780541478581 |
10 | 530226414307 |
11 | 19495aa95997 |
12 | 86917905917 |
13 | 3b0003b8025 |
14 | 1b93d768799 |
15 | dbd4582b57 |
hex | 7b73f502e3 |
530226414307 has 2 divisors, whose sum is σ = 530226414308. Its totient is φ = 530226414306.
The previous prime is 530226414229. The next prime is 530226414449. The reversal of 530226414307 is 703414622035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530226414307 - 215 = 530226381539 is a prime.
It is a super-2 number, since 2×5302264143072 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530226214307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265113207153 + 265113207154.
It is an arithmetic number, because the mean of its divisors is an integer number (265113207154).
Almost surely, 2530226414307 is an apocalyptic number.
530226414307 is a deficient number, since it is larger than the sum of its proper divisors (1).
530226414307 is an equidigital number, since it uses as much as digits as its factorization.
530226414307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 530226414307 in words is "five hundred thirty billion, two hundred twenty-six million, four hundred fourteen thousand, three hundred seven".
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