Base | Representation |
---|---|
bin | 110001011000011100… |
… | …010101110101100011 |
3 | 12001212021221102200010 |
4 | 301120130111311203 |
5 | 1332042444311120 |
6 | 40205244100003 |
7 | 3554653510260 |
oct | 613034256543 |
9 | 161767842603 |
10 | 53023432035 |
11 | 2053a388312 |
12 | a339534603 |
13 | 5000269872 |
14 | 27d00b6267 |
15 | 15a50167e0 |
hex | c58715d63 |
53023432035 has 32 divisors (see below), whose sum is σ = 97040724480. Its totient is φ = 24218385408.
The previous prime is 53023432001. The next prime is 53023432037.
53023432035 is nontrivially palindromic in base 10.
53023432035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53023432035 - 212 = 53023427939 is a prime.
It is a super-2 number, since 2×530234320352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53023431993 and 53023432011.
It is not an unprimeable number, because it can be changed into a prime (53023432037) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 94990 + ... + 339219.
It is an arithmetic number, because the mean of its divisors is an integer number (3032522640).
Almost surely, 253023432035 is an apocalyptic number.
53023432035 is a deficient number, since it is larger than the sum of its proper divisors (44017292445).
53023432035 is a wasteful number, since it uses less digits than its factorization.
53023432035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 435387.
The product of its (nonzero) digits is 32400, while the sum is 30.
The spelling of 53023432035 in words is "fifty-three billion, twenty-three million, four hundred thirty-two thousand, thirty-five".
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