Base | Representation |
---|---|
bin | 11000000111001101001011… |
… | …01101100001011110001111 |
3 | 20221202001121021121222111120 |
4 | 30003212211231201132033 |
5 | 23422221430232141333 |
6 | 304434543042052023 |
7 | 14111603621516403 |
oct | 1403464555413617 |
9 | 227661537558446 |
10 | 53024151443343 |
11 | 159934641756a3 |
12 | 5b4452904a013 |
13 | 2378204a35052 |
14 | d1454dcbd103 |
15 | 61e42e80bdb3 |
hex | 3039a5b6178f |
53024151443343 has 32 divisors (see below), whose sum is σ = 75576501245952. Its totient is φ = 32985871776000.
The previous prime is 53024151443299. The next prime is 53024151443359. The reversal of 53024151443343 is 34334415142035.
It is not a de Polignac number, because 53024151443343 - 229 = 53023614572431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53024151443295 and 53024151443304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53024151443443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48448618 + ... + 49530968.
It is an arithmetic number, because the mean of its divisors is an integer number (2361765663936).
Almost surely, 253024151443343 is an apocalyptic number.
53024151443343 is a deficient number, since it is larger than the sum of its proper divisors (22552349802609).
53024151443343 is a wasteful number, since it uses less digits than its factorization.
53024151443343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1099735.
The product of its (nonzero) digits is 1036800, while the sum is 42.
Adding to 53024151443343 its reverse (34334415142035), we get a palindrome (87358566585378).
The spelling of 53024151443343 in words is "fifty-three trillion, twenty-four billion, one hundred fifty-one million, four hundred forty-three thousand, three hundred forty-three".
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