Base | Representation |
---|---|
bin | 110001011000011111… |
… | …011001111111101001 |
3 | 12001212100110020210222 |
4 | 301120133121333221 |
5 | 1332043201013442 |
6 | 40205313215425 |
7 | 3554663364602 |
oct | 613037317751 |
9 | 161770406728 |
10 | 53024235497 |
11 | 2053a886a32 |
12 | a339861575 |
13 | 500048b49c |
14 | 27d0244da9 |
15 | 15a51248d2 |
hex | c587d9fe9 |
53024235497 has 2 divisors, whose sum is σ = 53024235498. Its totient is φ = 53024235496.
The previous prime is 53024235413. The next prime is 53024235499. The reversal of 53024235497 is 79453242035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53021509696 + 2725801 = 230264^2 + 1651^2 .
It is a cyclic number.
It is not a de Polignac number, because 53024235497 - 28 = 53024235241 is a prime.
Together with 53024235499, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53024235499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26512117748 + 26512117749.
It is an arithmetic number, because the mean of its divisors is an integer number (26512117749).
Almost surely, 253024235497 is an apocalyptic number.
It is an amenable number.
53024235497 is a deficient number, since it is larger than the sum of its proper divisors (1).
53024235497 is an equidigital number, since it uses as much as digits as its factorization.
53024235497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 907200, while the sum is 44.
The spelling of 53024235497 in words is "fifty-three billion, twenty-four million, two hundred thirty-five thousand, four hundred ninety-seven".
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