Base | Representation |
---|---|
bin | 100110100101001000100… |
… | …1011101100010001011101 |
3 | 200202220111010212110122221 |
4 | 1031022101023230101131 |
5 | 1143333331400421014 |
6 | 15135522310305341 |
7 | 1055042021166622 |
oct | 115122113542135 |
9 | 20686433773587 |
10 | 5302425404509 |
11 | 17648229a80a2 |
12 | 71778b658251 |
13 | 2c602a534b6c |
14 | 1448d2a7c349 |
15 | 92ddccc3b24 |
hex | 4d2912ec45d |
5302425404509 has 2 divisors, whose sum is σ = 5302425404510. Its totient is φ = 5302425404508.
The previous prime is 5302425404473. The next prime is 5302425404519. The reversal of 5302425404509 is 9054045242035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4486559422500 + 815865982009 = 2118150^2 + 903253^2 .
It is a cyclic number.
It is not a de Polignac number, because 5302425404509 - 239 = 4752669590621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5302425404519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651212702254 + 2651212702255.
It is an arithmetic number, because the mean of its divisors is an integer number (2651212702255).
Almost surely, 25302425404509 is an apocalyptic number.
It is an amenable number.
5302425404509 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302425404509 is an equidigital number, since it uses as much as digits as its factorization.
5302425404509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 5302425404509 in words is "five trillion, three hundred two billion, four hundred twenty-five million, four hundred four thousand, five hundred nine".
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