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5302425405071 is a prime number
BaseRepresentation
bin100110100101001000100…
…1011101100011010001111
3200202220111010212111102202
41031022101023230122033
51143333331400430241
615135522310312115
71055042021201354
oct115122113543217
920686433774382
105302425405071
1117648229a8563
1271778b65863b
132c602a5351b2
141448d2a7c62b
1592ddccc3d9b
hex4d2912ec68f

5302425405071 has 2 divisors, whose sum is σ = 5302425405072. Its totient is φ = 5302425405070.

The previous prime is 5302425405041. The next prime is 5302425405097. The reversal of 5302425405071 is 1705045242035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5302425405071 - 230 = 5301351663247 is a prime.

It is a super-3 number, since 3×53024254050713 (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5302425405041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651212702535 + 2651212702536.

It is an arithmetic number, because the mean of its divisors is an integer number (2651212702536).

Almost surely, 25302425405071 is an apocalyptic number.

5302425405071 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302425405071 is an equidigital number, since it uses as much as digits as its factorization.

5302425405071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 38.

The spelling of 5302425405071 in words is "five trillion, three hundred two billion, four hundred twenty-five million, four hundred five thousand, seventy-one".