Base | Representation |
---|---|
bin | 1111011011101001111… |
… | …00111100011001000111 |
3 | 1212200122112221220111011 |
4 | 13231310330330121013 |
5 | 32141414214013341 |
6 | 1043331302023051 |
7 | 53210630034154 |
oct | 7556474743107 |
9 | 1780575856434 |
10 | 530243110471 |
11 | 194969459a78 |
12 | 86921417a87 |
13 | 3b0039b2709 |
14 | 1b941a7322b |
15 | dbd5c7eb81 |
hex | 7b74f3c647 |
530243110471 has 2 divisors, whose sum is σ = 530243110472. Its totient is φ = 530243110470.
The previous prime is 530243110459. The next prime is 530243110669. The reversal of 530243110471 is 174011342035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530243110471 is a prime.
It is a super-3 number, since 3×5302431104713 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530243116471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265121555235 + 265121555236.
It is an arithmetic number, because the mean of its divisors is an integer number (265121555236).
Almost surely, 2530243110471 is an apocalyptic number.
530243110471 is a deficient number, since it is larger than the sum of its proper divisors (1).
530243110471 is an equidigital number, since it uses as much as digits as its factorization.
530243110471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 530243110471 in words is "five hundred thirty billion, two hundred forty-three million, one hundred ten thousand, four hundred seventy-one".
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