Base | Representation |
---|---|
bin | 1111011011101001111… |
… | …01100101101101001001 |
3 | 1212200122120021111121111 |
4 | 13231310331211231021 |
5 | 32141414234422224 |
6 | 1043331305410321 |
7 | 53210631340414 |
oct | 7556475455511 |
9 | 1780576244544 |
10 | 530243279689 |
11 | 194969565122 |
12 | 869214999a1 |
13 | 3b003a41746 |
14 | 1b941ab8b7b |
15 | dbd5cb4d94 |
hex | 7b74f65b49 |
530243279689 has 2 divisors, whose sum is σ = 530243279690. Its totient is φ = 530243279688.
The previous prime is 530243279677. The next prime is 530243279701. The reversal of 530243279689 is 986972342035.
It is a balanced prime because it is at equal distance from previous prime (530243279677) and next prime (530243279701).
It can be written as a sum of positive squares in only one way, i.e., 526483750464 + 3759529225 = 725592^2 + 61315^2 .
It is a cyclic number.
It is not a de Polignac number, because 530243279689 - 29 = 530243279177 is a prime.
It is not a weakly prime, because it can be changed into another prime (530243279989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265121639844 + 265121639845.
It is an arithmetic number, because the mean of its divisors is an integer number (265121639845).
Almost surely, 2530243279689 is an apocalyptic number.
It is an amenable number.
530243279689 is a deficient number, since it is larger than the sum of its proper divisors (1).
530243279689 is an equidigital number, since it uses as much as digits as its factorization.
530243279689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19595520, while the sum is 58.
The spelling of 530243279689 in words is "five hundred thirty billion, two hundred forty-three million, two hundred seventy-nine thousand, six hundred eighty-nine".
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