Base | Representation |
---|---|
bin | 110001011000100000… |
… | …000101000111010011 |
3 | 12001212100210020002101 |
4 | 301120200011013103 |
5 | 1332043222141430 |
6 | 40205321101231 |
7 | 3554665031533 |
oct | 613040050723 |
9 | 161770706071 |
10 | 53024412115 |
11 | 2053a9976a4 |
12 | a339927817 |
13 | 50005209ac |
14 | 27d028d4c3 |
15 | 15a515bdca |
hex | c588051d3 |
53024412115 has 4 divisors (see below), whose sum is σ = 63629294544. Its totient is φ = 42419529688.
The previous prime is 53024412019. The next prime is 53024412143. The reversal of 53024412115 is 51121442035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53024412115 - 29 = 53024411603 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5302441207 + ... + 5302441216.
It is an arithmetic number, because the mean of its divisors is an integer number (15907323636).
Almost surely, 253024412115 is an apocalyptic number.
53024412115 is a deficient number, since it is larger than the sum of its proper divisors (10604882429).
53024412115 is a wasteful number, since it uses less digits than its factorization.
53024412115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10604882428.
The product of its (nonzero) digits is 4800, while the sum is 28.
The spelling of 53024412115 in words is "fifty-three billion, twenty-four million, four hundred twelve thousand, one hundred fifteen".
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