Base | Representation |
---|---|
bin | 1111011011101010111… |
… | …00001100010100000001 |
3 | 1212200200010101002100111 |
4 | 13231311130030110001 |
5 | 32141423313132040 |
6 | 1043332153351321 |
7 | 53211056462455 |
oct | 7556534142401 |
9 | 1780603332314 |
10 | 530251302145 |
11 | 194973044554 |
12 | 86924108541 |
13 | 3b0055c0166 |
14 | 1b942ba6665 |
15 | dbd684bdea |
hex | 7b7570c501 |
530251302145 has 4 divisors (see below), whose sum is σ = 636301562580. Its totient is φ = 424201041712.
The previous prime is 530251302137. The next prime is 530251302167. The reversal of 530251302145 is 541203152035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 356505720561 + 173745581584 = 597081^2 + 416828^2 .
It is a cyclic number.
It is not a de Polignac number, because 530251302145 - 23 = 530251302137 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53025130210 + ... + 53025130219.
It is an arithmetic number, because the mean of its divisors is an integer number (159075390645).
Almost surely, 2530251302145 is an apocalyptic number.
It is an amenable number.
530251302145 is a deficient number, since it is larger than the sum of its proper divisors (106050260435).
530251302145 is a wasteful number, since it uses less digits than its factorization.
530251302145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106050260434.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 530251302145 in words is "five hundred thirty billion, two hundred fifty-one million, three hundred two thousand, one hundred forty-five".
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