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530251411021 is a prime number
BaseRepresentation
bin1111011011101010111…
…00100110111001001101
31212200200010120121200221
413231311130212321031
532141423330123041
61043332155551341
753211060425053
oct7556534467115
91780603517627
10530251411021
11194973109332
128692415b551
133b00562a897
141b942bd41d3
15dbd686e2d1
hex7b75726e4d

530251411021 has 2 divisors, whose sum is σ = 530251411022. Its totient is φ = 530251411020.

The previous prime is 530251411013. The next prime is 530251411033. The reversal of 530251411021 is 120114152035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 312241793796 + 218009617225 = 558786^2 + 466915^2 .

It is a cyclic number.

It is not a de Polignac number, because 530251411021 - 23 = 530251411013 is a prime.

It is a super-2 number, since 2×5302514110212 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530251411061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265125705510 + 265125705511.

It is an arithmetic number, because the mean of its divisors is an integer number (265125705511).

Almost surely, 2530251411021 is an apocalyptic number.

It is an amenable number.

530251411021 is a deficient number, since it is larger than the sum of its proper divisors (1).

530251411021 is an equidigital number, since it uses as much as digits as its factorization.

530251411021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 530251411021 its reverse (120114152035), we get a palindrome (650365563056).

The spelling of 530251411021 in words is "five hundred thirty billion, two hundred fifty-one million, four hundred eleven thousand, twenty-one".