Base | Representation |
---|---|
bin | 1111011011101010111… |
… | …10111001101111010111 |
3 | 1212200200011201011210001 |
4 | 13231311132321233113 |
5 | 32141424003400003 |
6 | 1043332220512131 |
7 | 53211065511463 |
oct | 7556536715727 |
9 | 1780604634701 |
10 | 530252012503 |
11 | 19497348a224 |
12 | 869243ab647 |
13 | 3b0057ab5a5 |
14 | 1b942d0d4a3 |
15 | dbd693c61d |
hex | 7b757b9bd7 |
530252012503 has 4 divisors (see below), whose sum is σ = 530288368128. Its totient is φ = 530215656880.
The previous prime is 530252012387. The next prime is 530252012539. The reversal of 530252012503 is 305210252035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530252012503 - 213 = 530252004311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530252012203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18155926 + ... + 18185107.
It is an arithmetic number, because the mean of its divisors is an integer number (132572092032).
Almost surely, 2530252012503 is an apocalyptic number.
530252012503 is a deficient number, since it is larger than the sum of its proper divisors (36355625).
530252012503 is a wasteful number, since it uses less digits than its factorization.
530252012503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36355624.
The product of its (nonzero) digits is 9000, while the sum is 28.
Adding to 530252012503 its reverse (305210252035), we get a palindrome (835462264538).
It can be divided in two parts, 53025 and 2012503, that added together give a triangular number (2065528 = T2032).
The spelling of 530252012503 in words is "five hundred thirty billion, two hundred fifty-two million, twelve thousand, five hundred three".
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