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5302523441 is a prime number
BaseRepresentation
bin1001111000000111…
…00001011000110001
3111200112122002201002
410330003201120301
541324421222231
62234055251345
7245254464005
oct47403413061
914615562632
105302523441
112281155386
12103b979b55
13666731147
14384330705
152107b30cb
hex13c0e1631

5302523441 has 2 divisors, whose sum is σ = 5302523442. Its totient is φ = 5302523440.

The previous prime is 5302523419. The next prime is 5302523453. The reversal of 5302523441 is 1443252035.

It is a happy number.

5302523441 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4178329600 + 1124193841 = 64640^2 + 33529^2 .

It is a cyclic number.

It is not a de Polignac number, because 5302523441 - 214 = 5302507057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (5302523491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651261720 + 2651261721.

It is an arithmetic number, because the mean of its divisors is an integer number (2651261721).

Almost surely, 25302523441 is an apocalyptic number.

It is an amenable number.

5302523441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302523441 is an equidigital number, since it uses as much as digits as its factorization.

5302523441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 29.

The square root of 5302523441 is about 72818.4278943181. The cubic root of 5302523441 is about 1743.7900651098.

Adding to 5302523441 its reverse (1443252035), we get a palindrome (6745775476).

The spelling of 5302523441 in words is "five billion, three hundred two million, five hundred twenty-three thousand, four hundred forty-one".