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53025300525317 is a prime number
BaseRepresentation
bin11000000111001111010100…
…01100111011000100000101
320221202011120100211101122012
430003213222030323010011
523422231303413302232
6304435253050544005
714111644243534541
oct1403475214730405
9227664510741565
1053025300525317
11159939a3863a1a
125b447a9a38005
132378358b0c303
14d1461c756a21
1561e49a63a9b2
hex3039ea33b105

53025300525317 has 2 divisors, whose sum is σ = 53025300525318. Its totient is φ = 53025300525316.

The previous prime is 53025300525283. The next prime is 53025300525349. The reversal of 53025300525317 is 71352500352035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49521043820161 + 3504256705156 = 7037119^2 + 1871966^2 .

It is a cyclic number.

It is not a de Polignac number, because 53025300525317 - 28 = 53025300525061 is a prime.

It is a super-3 number, since 3×530253005253173 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53025300521317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26512650262658 + 26512650262659.

It is an arithmetic number, because the mean of its divisors is an integer number (26512650262659).

Almost surely, 253025300525317 is an apocalyptic number.

It is an amenable number.

53025300525317 is a deficient number, since it is larger than the sum of its proper divisors (1).

53025300525317 is an equidigital number, since it uses as much as digits as its factorization.

53025300525317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 472500, while the sum is 41.

The spelling of 53025300525317 in words is "fifty-three trillion, twenty-five billion, three hundred million, five hundred twenty-five thousand, three hundred seventeen".