Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111010100101100001 |
3 | 200202220210011112011211121 |
4 | 1031022120002322211201 |
5 | 1143334100334404403 |
6 | 15135541542212241 |
7 | 1055044616646403 |
oct | 115123002724541 |
9 | 20686704464747 |
10 | 5302540544353 |
11 | 176488199a398 |
12 | 717802124081 |
13 | 2c6048349850 |
14 | 144904090b73 |
15 | 92de7e693bd |
hex | 4d2980ba961 |
5302540544353 has 8 divisors (see below), whose sum is σ = 5710576975488. Its totient is φ = 4894525355664.
The previous prime is 5302540544341. The next prime is 5302540544387. The reversal of 5302540544353 is 3534450452035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5302540544353 - 25 = 5302540544321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302540544153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4790275 + ... + 5792392.
It is an arithmetic number, because the mean of its divisors is an integer number (713822121936).
Almost surely, 25302540544353 is an apocalyptic number.
It is an amenable number.
5302540544353 is a deficient number, since it is larger than the sum of its proper divisors (408036431135).
5302540544353 is a wasteful number, since it uses less digits than its factorization.
5302540544353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10621223.
The product of its (nonzero) digits is 2160000, while the sum is 43.
Adding to 5302540544353 its reverse (3534450452035), we get a palindrome (8836990996388).
The spelling of 5302540544353 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred forty-four thousand, three hundred fifty-three".
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