Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111100110010111011 |
3 | 200202220210011112122020210 |
4 | 1031022120002330302323 |
5 | 1143334100340202103 |
6 | 15135541542322203 |
7 | 1055044620014652 |
oct | 115123002746273 |
9 | 20686704478223 |
10 | 5302540553403 |
11 | 17648819a6175 |
12 | 717802129363 |
13 | 2c60483509c2 |
14 | 144904094199 |
15 | 92de7e6be03 |
hex | 4d2980bccbb |
5302540553403 has 4 divisors (see below), whose sum is σ = 7070054071208. Its totient is φ = 3535027035600.
The previous prime is 5302540553393. The next prime is 5302540553407. The reversal of 5302540553403 is 3043550452035.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5302540553403 - 217 = 5302540422331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302540553407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 883756758898 + ... + 883756758903.
It is an arithmetic number, because the mean of its divisors is an integer number (1767513517802).
Almost surely, 25302540553403 is an apocalyptic number.
5302540553403 is a deficient number, since it is larger than the sum of its proper divisors (1767513517805).
5302540553403 is a wasteful number, since it uses less digits than its factorization.
5302540553403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1767513517804.
The product of its (nonzero) digits is 540000, while the sum is 39.
The spelling of 5302540553403 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-three thousand, four hundred three".
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