Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111100110010111111 |
3 | 200202220210011112122020221 |
4 | 1031022120002330302333 |
5 | 1143334100340202112 |
6 | 15135541542322211 |
7 | 1055044620014656 |
oct | 115123002746277 |
9 | 20686704478227 |
10 | 5302540553407 |
11 | 17648819a6179 |
12 | 717802129367 |
13 | 2c60483509c6 |
14 | 14490409419d |
15 | 92de7e6be07 |
hex | 4d2980bccbf |
5302540553407 has 2 divisors, whose sum is σ = 5302540553408. Its totient is φ = 5302540553406.
The previous prime is 5302540553393. The next prime is 5302540553411. The reversal of 5302540553407 is 7043550452035.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5302540553407 - 27 = 5302540553279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5302540553437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651270276703 + 2651270276704.
It is an arithmetic number, because the mean of its divisors is an integer number (2651270276704).
Almost surely, 25302540553407 is an apocalyptic number.
5302540553407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302540553407 is an equidigital number, since it uses as much as digits as its factorization.
5302540553407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260000, while the sum is 43.
The spelling of 5302540553407 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-three thousand, four hundred seven".
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