Base | Representation |
---|---|
bin | 100110100101001100001… |
… | …0100110111011011111010 |
3 | 200202220210111101020211101 |
4 | 1031022120110313123322 |
5 | 1143334103041000132 |
6 | 15135542231122014 |
7 | 1055045004645535 |
oct | 115123024673372 |
9 | 20686714336741 |
10 | 5302545250042 |
11 | 1764884613897 |
12 | 71780381330a |
13 | 2c6049306691 |
14 | 144904957a1c |
15 | 92de85987e7 |
hex | 4d2985376fa |
5302545250042 has 8 divisors (see below), whose sum is σ = 8299636043616. Its totient is φ = 2535999902172.
The previous prime is 5302545250003. The next prime is 5302545250043. The reversal of 5302545250042 is 2400525452035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×53025452500423 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 5302545249983 and 5302545250010.
It is not an unprimeable number, because it can be changed into a prime (5302545250043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57636361368 + ... + 57636361459.
It is an arithmetic number, because the mean of its divisors is an integer number (1037454505452).
Almost surely, 25302545250042 is an apocalyptic number.
5302545250042 is a deficient number, since it is larger than the sum of its proper divisors (2997090793574).
5302545250042 is a wasteful number, since it uses less digits than its factorization.
5302545250042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115272722852.
The product of its (nonzero) digits is 240000, while the sum is 37.
The spelling of 5302545250042 in words is "five trillion, three hundred two billion, five hundred forty-five million, two hundred fifty thousand, forty-two".
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