Base | Representation |
---|---|
bin | 11000000111010100011101… |
… | …01011101010110111001111 |
3 | 20221202102200200100201021101 |
4 | 30003222032223222313033 |
5 | 23422302431333030342 |
6 | 304440430545043531 |
7 | 14112102522231622 |
oct | 1403521653526717 |
9 | 227672620321241 |
10 | 53028060048847 |
11 | 1599508a505884 |
12 | 5b4523a0265a7 |
13 | 23786a8736b80 |
14 | d14801041db9 |
15 | 61e5aca2c3b7 |
hex | 303a8eaeadcf |
53028060048847 has 16 divisors (see below), whose sum is σ = 58668510064192. Its totient is φ = 47611471645440.
The previous prime is 53028060048781. The next prime is 53028060048889. The reversal of 53028060048847 is 74884006082035.
It is a cyclic number.
It is not a de Polignac number, because 53028060048847 - 215 = 53028060016079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53028060040847) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15278598 + ... + 18425299.
It is an arithmetic number, because the mean of its divisors is an integer number (3666781879012).
Almost surely, 253028060048847 is an apocalyptic number.
53028060048847 is a deficient number, since it is larger than the sum of its proper divisors (5640450015345).
53028060048847 is a wasteful number, since it uses less digits than its factorization.
53028060048847 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33707218.
The product of its (nonzero) digits is 10321920, while the sum is 55.
The spelling of 53028060048847 in words is "fifty-three trillion, twenty-eight billion, sixty million, forty-eight thousand, eight hundred forty-seven".
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