Base | Representation |
---|---|
bin | 100110100101011010011… |
… | …0000011100010100101011 |
3 | 200202222000201220220111122 |
4 | 1031022310300130110223 |
5 | 1143341042143203232 |
6 | 15140101430445455 |
7 | 1055062556212115 |
oct | 115126460342453 |
9 | 20688021826448 |
10 | 5303022241067 |
11 | 1764aa9895251 |
12 | 71791750388b |
13 | 2c60c40938a5 |
14 | 14494c0403b5 |
15 | 92e253b9312 |
hex | 4d2b4c1c52b |
5303022241067 has 2 divisors, whose sum is σ = 5303022241068. Its totient is φ = 5303022241066.
The previous prime is 5303022241043. The next prime is 5303022241091. The reversal of 5303022241067 is 7601422203035.
It is a balanced prime because it is at equal distance from previous prime (5303022241043) and next prime (5303022241091).
It is a cyclic number.
It is not a de Polignac number, because 5303022241067 - 28 = 5303022240811 is a prime.
It is a super-2 number, since 2×53030222410672 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5303022241267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651511120533 + 2651511120534.
It is an arithmetic number, because the mean of its divisors is an integer number (2651511120534).
Almost surely, 25303022241067 is an apocalyptic number.
5303022241067 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303022241067 is an equidigital number, since it uses as much as digits as its factorization.
5303022241067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
The spelling of 5303022241067 in words is "five trillion, three hundred three billion, twenty-two million, two hundred forty-one thousand, sixty-seven".
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