Base | Representation |
---|---|
bin | 100110100101011011010… |
… | …0011111000111110101011 |
3 | 200202222002211212110211011 |
4 | 1031022312203320332223 |
5 | 1143341122420130003 |
6 | 15140104431244351 |
7 | 1055063404360141 |
oct | 115126643707653 |
9 | 20688084773734 |
10 | 5303052505003 |
11 | 1765014985a70 |
12 | 7179256796b7 |
13 | 2c60ca42ba46 |
14 | 14495207b591 |
15 | 92e27d9646d |
hex | 4d2b68f8fab |
5303052505003 has 8 divisors (see below), whose sum is σ = 5786239170816. Its totient is φ = 4820047669800.
The previous prime is 5303052504913. The next prime is 5303052505019. The reversal of 5303052505003 is 3005052503035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5303052505003 - 213 = 5303052496811 is a prime.
It is a super-3 number, since 3×53030525050033 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5303052505103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45396663 + ... + 45513328.
It is an arithmetic number, because the mean of its divisors is an integer number (723279896352).
Almost surely, 25303052505003 is an apocalyptic number.
5303052505003 is a deficient number, since it is larger than the sum of its proper divisors (483186665813).
5303052505003 is a wasteful number, since it uses less digits than its factorization.
5303052505003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90915305.
The product of its (nonzero) digits is 33750, while the sum is 31.
The spelling of 5303052505003 in words is "five trillion, three hundred three billion, fifty-two million, five hundred five thousand, three".
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