Base | Representation |
---|---|
bin | 111100010010011110101010… |
… | …0011011010001101110011100 |
3 | 2120112122200201210012020221011 |
4 | 1320210331110123101232130 |
5 | 1024002010300300103202 |
6 | 5115510522525545004 |
7 | 216462203164103665 |
oct | 17044752433215634 |
9 | 2515580653166834 |
10 | 530305323441052 |
11 | 143a76252062185 |
12 | 4b588883a15164 |
13 | 199b97677a7953 |
14 | 94d4cb396236c |
15 | 41496d23cbbd7 |
hex | 1e24f546d1b9c |
530305323441052 has 6 divisors (see below), whose sum is σ = 928034316021848. Its totient is φ = 265152661720524.
The previous prime is 530305323441031. The next prime is 530305323441083. The reversal of 530305323441052 is 250144323503035.
It is a super-3 number, since 3×5303053234410523 (a number of 45 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530305323440996 and 530305323441014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66288165430128 + ... + 66288165430135.
Almost surely, 2530305323441052 is an apocalyptic number.
It is an amenable number.
530305323441052 is a deficient number, since it is larger than the sum of its proper divisors (397728992580796).
530305323441052 is a wasteful number, since it uses less digits than its factorization.
530305323441052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132576330860267 (or 132576330860265 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 530305323441052 its reverse (250144323503035), we get a palindrome (780449646944087).
The spelling of 530305323441052 in words is "five hundred thirty trillion, three hundred five billion, three hundred twenty-three million, four hundred forty-one thousand, fifty-two".
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