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530305323441052 = 22132576330860263
BaseRepresentation
bin111100010010011110101010…
…0011011010001101110011100
32120112122200201210012020221011
41320210331110123101232130
51024002010300300103202
65115510522525545004
7216462203164103665
oct17044752433215634
92515580653166834
10530305323441052
11143a76252062185
124b588883a15164
13199b97677a7953
1494d4cb396236c
1541496d23cbbd7
hex1e24f546d1b9c

530305323441052 has 6 divisors (see below), whose sum is σ = 928034316021848. Its totient is φ = 265152661720524.

The previous prime is 530305323441031. The next prime is 530305323441083. The reversal of 530305323441052 is 250144323503035.

It is a super-3 number, since 3×5303053234410523 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 530305323440996 and 530305323441014.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66288165430128 + ... + 66288165430135.

Almost surely, 2530305323441052 is an apocalyptic number.

It is an amenable number.

530305323441052 is a deficient number, since it is larger than the sum of its proper divisors (397728992580796).

530305323441052 is a wasteful number, since it uses less digits than its factorization.

530305323441052 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132576330860267 (or 132576330860265 counting only the distinct ones).

The product of its (nonzero) digits is 648000, while the sum is 40.

Adding to 530305323441052 its reverse (250144323503035), we get a palindrome (780449646944087).

The spelling of 530305323441052 in words is "five hundred thirty trillion, three hundred five billion, three hundred twenty-three million, four hundred forty-one thousand, fifty-two".

Divisors: 1 2 4 132576330860263 265152661720526 530305323441052