Base | Representation |
---|---|
bin | 100110100101011011010… |
… | …1011010101011001011101 |
3 | 200202222002222112121122121 |
4 | 1031022312223111121131 |
5 | 1143341123420101123 |
6 | 15140104541142541 |
7 | 1055063430065320 |
oct | 115126653253135 |
9 | 20688088477577 |
10 | 5303054456413 |
11 | 1765015a990aa |
12 | 71792625aa51 |
13 | 2c60ca96301c |
14 | 1449524287b7 |
15 | 92e2812e75d |
hex | 4d2b6ad565d |
5303054456413 has 16 divisors (see below), whose sum is σ = 6418398801024. Its totient is φ = 4277256168960.
The previous prime is 5303054456387. The next prime is 5303054456419. The reversal of 5303054456413 is 3146544503035.
It is a cyclic number.
It is not a de Polignac number, because 5303054456413 - 217 = 5303054325341 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5303054456413.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303054456419) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3755248 + ... + 4970713.
It is an arithmetic number, because the mean of its divisors is an integer number (401149925064).
Almost surely, 25303054456413 is an apocalyptic number.
It is an amenable number.
5303054456413 is a deficient number, since it is larger than the sum of its proper divisors (1115344344611).
5303054456413 is a wasteful number, since it uses less digits than its factorization.
5303054456413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8731092.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 5303054456413 its reverse (3146544503035), we get a palindrome (8449598959448).
The spelling of 5303054456413 in words is "five trillion, three hundred three billion, fifty-four million, four hundred fifty-six thousand, four hundred thirteen".
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