Base | Representation |
---|---|
bin | 11000000111011010101110… |
… | …11001111101010100011111 |
3 | 20221202202101101001101001011 |
4 | 30003231113121331110133 |
5 | 23422331330433020041 |
6 | 304442145044000051 |
7 | 14112252133200613 |
oct | 1403552731752437 |
9 | 227682341041034 |
10 | 53031427626271 |
11 | 15996558406616 |
12 | 5b45a19990027 |
13 | 2378ac431a133 |
14 | d14a403ad343 |
15 | 61e7084cce81 |
hex | 303b5767d51f |
53031427626271 has 2 divisors, whose sum is σ = 53031427626272. Its totient is φ = 53031427626270.
The previous prime is 53031427626239. The next prime is 53031427626277. The reversal of 53031427626271 is 17262672413035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53031427626271 - 25 = 53031427626239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53031427626277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26515713813135 + 26515713813136.
It is an arithmetic number, because the mean of its divisors is an integer number (26515713813136).
Almost surely, 253031427626271 is an apocalyptic number.
53031427626271 is a deficient number, since it is larger than the sum of its proper divisors (1).
53031427626271 is an equidigital number, since it uses as much as digits as its factorization.
53031427626271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2540160, while the sum is 49.
The spelling of 53031427626271 in words is "fifty-three trillion, thirty-one billion, four hundred twenty-seven million, six hundred twenty-six thousand, two hundred seventy-one".
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