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530315010143551 is a prime number
BaseRepresentation
bin111100010010100011001010…
…1110011000111010100111111
32120112200121201212102201200101
41320211012111303013110333
51024002140120044043201
65115515204041341531
7216462665215524103
oct17045062563072477
92515617655381611
10530315010143551
11143a7a372a40136
124b58a727a978a7
13199ba64c5bc889
1494d555224d903
154149a9ca00d01
hex1e25195cc753f

530315010143551 has 2 divisors, whose sum is σ = 530315010143552. Its totient is φ = 530315010143550.

The previous prime is 530315010143531. The next prime is 530315010143557. The reversal of 530315010143551 is 155341010513035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 530315010143551 - 27 = 530315010143423 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 530315010143551.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530315010143557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265157505071775 + 265157505071776.

It is an arithmetic number, because the mean of its divisors is an integer number (265157505071776).

Almost surely, 2530315010143551 is an apocalyptic number.

530315010143551 is a deficient number, since it is larger than the sum of its proper divisors (1).

530315010143551 is an equidigital number, since it uses as much as digits as its factorization.

530315010143551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67500, while the sum is 37.

Adding to 530315010143551 its reverse (155341010513035), we get a palindrome (685656020656586).

The spelling of 530315010143551 in words is "five hundred thirty trillion, three hundred fifteen billion, ten million, one hundred forty-three thousand, five hundred fifty-one".