Base | Representation |
---|---|
bin | 1111011011110011101… |
… | …01011110110010101101 |
3 | 1212200212021010101002022 |
4 | 13231321311132302231 |
5 | 32142101202242201 |
6 | 1043343350035525 |
7 | 53212643315510 |
oct | 7557165366255 |
9 | 1780767111068 |
10 | 530325040301 |
11 | 194a00729081 |
12 | 86944948ba5 |
13 | 3b01796a2c4 |
14 | 1b94c8bcd77 |
15 | dbdd06541b |
hex | 7b79d5ecad |
530325040301 has 8 divisors (see below), whose sum is σ = 606101370624. Its totient is φ = 454552612560.
The previous prime is 530325040283. The next prime is 530325040307. The reversal of 530325040301 is 103040523035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530325040301 - 222 = 530320845997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530325040307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 678410 + ... + 1233243.
It is an arithmetic number, because the mean of its divisors is an integer number (75762671328).
Almost surely, 2530325040301 is an apocalyptic number.
It is an amenable number.
530325040301 is a deficient number, since it is larger than the sum of its proper divisors (75776330323).
530325040301 is a wasteful number, since it uses less digits than its factorization.
530325040301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1951291.
The product of its (nonzero) digits is 5400, while the sum is 26.
Adding to 530325040301 its reverse (103040523035), we get a palindrome (633365563336).
The spelling of 530325040301 in words is "five hundred thirty billion, three hundred twenty-five million, forty thousand, three hundred one".
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