Base | Representation |
---|---|
bin | 111100010010101000100001… |
… | …1001111111001110110101111 |
3 | 2120112201201102022121012121022 |
4 | 1320211101003033321312233 |
5 | 1024002332143040133003 |
6 | 5115524345125124355 |
7 | 216463553205433610 |
oct | 17045210317716657 |
9 | 2515651368535538 |
10 | 530326510083503 |
11 | 143a842343a4241 |
12 | 4b5909b72596bb |
13 | 199bb762c7ab83 |
14 | 94d5d2369bc07 |
15 | 414a0223e5738 |
hex | 1e254433f9daf |
530326510083503 has 8 divisors (see below), whose sum is σ = 607775705948160. Its totient is φ = 453299380682040.
The previous prime is 530326510083499. The next prime is 530326510083509. The reversal of 530326510083503 is 305380015623035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530326510083503 - 22 = 530326510083499 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530326510083509) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105516613103 + ... + 105516618128.
It is an arithmetic number, because the mean of its divisors is an integer number (75971963243520).
Almost surely, 2530326510083503 is an apocalyptic number.
530326510083503 is a deficient number, since it is larger than the sum of its proper divisors (77449195864657).
530326510083503 is a wasteful number, since it uses less digits than its factorization.
530326510083503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211033231597.
The product of its (nonzero) digits is 972000, while the sum is 44.
The spelling of 530326510083503 in words is "five hundred thirty trillion, three hundred twenty-six billion, five hundred ten million, eighty-three thousand, five hundred three".
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