Base | Representation |
---|---|
bin | 111100010010101010110100… |
… | …0001001100000111110101011 |
3 | 2120112202012002210020210021211 |
4 | 1320211111220021200332223 |
5 | 1024002422224034224120 |
6 | 5115530520510213551 |
7 | 216464116035242620 |
oct | 17045255011407653 |
9 | 2515665083223254 |
10 | 530331424133035 |
11 | 143a863262363a8 |
12 | 4b591948ab42b7 |
13 | 199bc067074aa5 |
14 | 94d626c188347 |
15 | 414a20da2025a |
hex | 1e25568260fab |
530331424133035 has 32 divisors (see below), whose sum is σ = 734520052328832. Its totient is φ = 360051712588800.
The previous prime is 530331424132999. The next prime is 530331424133039.
530331424133035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 530331424133035 - 239 = 529781668319147 is a prime.
It is a super-2 number, since 2×5303314241330352 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (530331424133039) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 384191239 + ... + 385569151.
It is an arithmetic number, because the mean of its divisors is an integer number (22953751635276).
Almost surely, 2530331424133035 is an apocalyptic number.
530331424133035 is a deficient number, since it is larger than the sum of its proper divisors (204188628195797).
530331424133035 is a wasteful number, since it uses less digits than its factorization.
530331424133035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1486903.
The product of its (nonzero) digits is 583200, while the sum is 40.
The spelling of 530331424133035 in words is "five hundred thirty trillion, three hundred thirty-one billion, four hundred twenty-four million, one hundred thirty-three thousand, thirty-five".
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