5303334983 has 2 divisors, whose sum is σ = 5303334984. Its totient is φ = 5303334982.

The previous prime is 5303334973. The next prime is 5303334991. The reversal of 5303334983 is 3894333035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5303334983 - 2³² = 1008367687 is a prime.

It is a super-2 number, since 2×5303334983² = 56250723883823220578, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5303334983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5303334913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651667491 + 2651667492.

It is an arithmetic number, because the mean of its divisors is an integer number (2651667492).

Almost surely, 2^5303334983 is an apocalyptic number.

5303334983 is a deficient number, since it is larger than the sum of its proper divisors (1).

5303334983 is an equidigital number, since it uses as much as digits as its factorization.

5303334983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 349920, while the sum is 41.

The square root of 5303334983 is about 72824.0000480611. Note that the first 4 decimals coincide. The cubic root of 5303334983 is about 1743.8790219183.

The spelling of 5303334983 in words is "five billion, three hundred three million, three hundred thirty-four thousand, nine hundred eighty-three".