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53033535341 = 372695328397
BaseRepresentation
bin110001011001000010…
…111000011101101101
312001212222221201210122
4301121002320131231
51332103041112331
640210244414325
73555135420053
oct613102703555
9161788851718
1053033535341
1120545059056
12a3409a73a5
135002396457
1427d15861d3
1515a5d6017b
hexc590b876d

53033535341 has 8 divisors (see below), whose sum is σ = 54669363480. Its totient is φ = 51408364608.

The previous prime is 53033535329. The next prime is 53033535349. The reversal of 53033535341 is 14353533035.

53033535341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 11398765225 + 41634770116 = 106765^2 + 204046^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53033535341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53033535349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2654246 + ... + 2674151.

It is an arithmetic number, because the mean of its divisors is an integer number (6833670435).

Almost surely, 253033535341 is an apocalyptic number.

It is an amenable number.

53033535341 is a deficient number, since it is larger than the sum of its proper divisors (1635828139).

53033535341 is a wasteful number, since it uses less digits than its factorization.

53033535341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5328703.

The product of its (nonzero) digits is 121500, while the sum is 35.

The spelling of 53033535341 in words is "fifty-three billion, thirty-three million, five hundred thirty-five thousand, three hundred forty-one".

Divisors: 1 37 269 9953 5328397 197150689 1433338793 53033535341