Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1101001010101001101101 |
3 | 200210000002022202100202210 |
4 | 1031023031031022221231 |
5 | 1143342412200032140 |
6 | 15140210242241033 |
7 | 1055105666544630 |
oct | 115131515125155 |
9 | 20700068670683 |
10 | 5303432424045 |
11 | 176519a385848 |
12 | 717a10956179 |
13 | 2c615b05c102 |
14 | 14498a6d5c17 |
15 | 92e4b3ded80 |
hex | 4d2cd34aa6d |
5303432424045 has 16 divisors (see below), whose sum is σ = 9697705004160. Its totient is φ = 2424426250944.
The previous prime is 5303432424011. The next prime is 5303432424071. The reversal of 5303432424045 is 5404242343035.
It is not a de Polignac number, because 5303432424045 - 215 = 5303432391277 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5303432423994 and 5303432424012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25254440010 + ... + 25254440219.
It is an arithmetic number, because the mean of its divisors is an integer number (606106562760).
Almost surely, 25303432424045 is an apocalyptic number.
It is an amenable number.
5303432424045 is a deficient number, since it is larger than the sum of its proper divisors (4394272580115).
5303432424045 is a wasteful number, since it uses less digits than its factorization.
5303432424045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50508880244.
The product of its (nonzero) digits is 691200, while the sum is 39.
The spelling of 5303432424045 in words is "five trillion, three hundred three billion, four hundred thirty-two million, four hundred twenty-four thousand, forty-five".
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