Base | Representation |
---|---|
bin | 100110100101101000101… |
… | …1011101000100010100001 |
3 | 200210000021021011112001212 |
4 | 1031023101123220202201 |
5 | 1143343033322402340 |
6 | 15140221254035505 |
7 | 1055110520314151 |
oct | 115132133504241 |
9 | 20700237145055 |
10 | 5303503325345 |
11 | 1765226401a65 |
12 | 717a30648b95 |
13 | 2c616c954c44 |
14 | 144995cb0761 |
15 | 92e52747a65 |
hex | 4d2d16e88a1 |
5303503325345 has 4 divisors (see below), whose sum is σ = 6364203990420. Its totient is φ = 4242802660272.
The previous prime is 5303503325339. The next prime is 5303503325357. The reversal of 5303503325345 is 5435233053035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2355908800609 + 2947594524736 = 1534897^2 + 1716856^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303503325345 - 232 = 5299208358049 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530350332530 + ... + 530350332539.
It is an arithmetic number, because the mean of its divisors is an integer number (1591050997605).
Almost surely, 25303503325345 is an apocalyptic number.
It is an amenable number.
5303503325345 is a deficient number, since it is larger than the sum of its proper divisors (1060700665075).
5303503325345 is a wasteful number, since it uses less digits than its factorization.
5303503325345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1060700665074.
The product of its (nonzero) digits is 1215000, while the sum is 41.
The spelling of 5303503325345 in words is "five trillion, three hundred three billion, five hundred three million, three hundred twenty-five thousand, three hundred forty-five".
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