Base | Representation |
---|---|
bin | 100110100101101000111… |
… | …0101010000111100010011 |
3 | 200210000021201210212221001 |
4 | 1031023101311100330103 |
5 | 1143343042032410220 |
6 | 15140222054042431 |
7 | 1055110631400301 |
oct | 115132165207423 |
9 | 20700251725831 |
10 | 5303510044435 |
11 | 176522a181129 |
12 | 717a32949417 |
13 | 2c6171168335 |
14 | 144996b3d271 |
15 | 92e5312380a |
hex | 4d2d1d50f13 |
5303510044435 has 8 divisors (see below), whose sum is σ = 6366607331616. Its totient is φ = 4241211183360.
The previous prime is 5303510044403. The next prime is 5303510044447. The reversal of 5303510044435 is 5344400153035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5303510044435 - 25 = 5303510044403 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5303510044394 and 5303510044403.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199591911 + ... + 199618480.
It is an arithmetic number, because the mean of its divisors is an integer number (795825916452).
Almost surely, 25303510044435 is an apocalyptic number.
5303510044435 is a deficient number, since it is larger than the sum of its proper divisors (1063097287181).
5303510044435 is a wasteful number, since it uses less digits than its factorization.
5303510044435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 399213053.
The product of its (nonzero) digits is 216000, while the sum is 37.
The spelling of 5303510044435 in words is "five trillion, three hundred three billion, five hundred ten million, forty-four thousand, four hundred thirty-five".
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