Base | Representation |
---|---|
bin | 11000000111100001110100… |
… | …10010100101110101111011 |
3 | 20221210010012122122110002100 |
4 | 30003300322102211311323 |
5 | 23422412124413420011 |
6 | 304444014502234443 |
7 | 14112445353656241 |
oct | 1403607222456573 |
9 | 227703178573070 |
10 | 53035234123131 |
11 | 15998131044a97 |
12 | 5b46700725a23 |
13 | 237927cb1a740 |
14 | d14cc1b52791 |
15 | 61e87c77dd56 |
hex | 303c3a4a5d7b |
53035234123131 has 48 divisors (see below), whose sum is σ = 83111283571680. Its totient is φ = 32395049832960.
The previous prime is 53035234123103. The next prime is 53035234123133. The reversal of 53035234123131 is 13132143253035.
53035234123131 is a `hidden beast` number, since 5 + 3 + 0 + 3 + 52 + 341 + 231 + 31 = 666.
It is not a de Polignac number, because 53035234123131 - 25 = 53035234123099 is a prime.
It is a super-2 number, since 2×530352341231312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53035234123133) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 73098991 + ... + 73820951.
It is an arithmetic number, because the mean of its divisors is an integer number (1731485074410).
Almost surely, 253035234123131 is an apocalyptic number.
53035234123131 is a deficient number, since it is larger than the sum of its proper divisors (30076049448549).
53035234123131 is a wasteful number, since it uses less digits than its factorization.
53035234123131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 726636 (or 726633 counting only the distinct ones).
The product of its (nonzero) digits is 97200, while the sum is 36.
Adding to 53035234123131 its reverse (13132143253035), we get a palindrome (66167377376166).
The spelling of 53035234123131 in words is "fifty-three trillion, thirty-five billion, two hundred thirty-four million, one hundred twenty-three thousand, one hundred thirty-one".
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