Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1001101001110100001001 |
3 | 200210000100212012222120121 |
4 | 1031023103221221310021 |
5 | 1143343122340230032 |
6 | 15140225104023241 |
7 | 1055111451623365 |
oct | 115132351516411 |
9 | 20700325188517 |
10 | 5303540555017 |
11 | 1765245420191 |
12 | 717a41001b21 |
13 | 2c617758b833 |
14 | 14499ac022a5 |
15 | 92e55b4da97 |
hex | 4d2d3a69d09 |
5303540555017 has 2 divisors, whose sum is σ = 5303540555018. Its totient is φ = 5303540555016.
The previous prime is 5303540554993. The next prime is 5303540555029. The reversal of 5303540555017 is 7105550453035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4380213666816 + 923326888201 = 2092896^2 + 960899^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5303540555017 is a prime.
It is not a weakly prime, because it can be changed into another prime (5303540555717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651770277508 + 2651770277509.
It is an arithmetic number, because the mean of its divisors is an integer number (2651770277509).
Almost surely, 25303540555017 is an apocalyptic number.
It is an amenable number.
5303540555017 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303540555017 is an equidigital number, since it uses as much as digits as its factorization.
5303540555017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 787500, while the sum is 43.
The spelling of 5303540555017 in words is "five trillion, three hundred three billion, five hundred forty million, five hundred fifty-five thousand, seventeen".
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