Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1001101001111111000101 |
3 | 200210000100212020000112112 |
4 | 1031023103221221333011 |
5 | 1143343122340240332 |
6 | 15140225104030405 |
7 | 1055111451625415 |
oct | 115132351517705 |
9 | 20700325200475 |
10 | 5303540555717 |
11 | 1765245420768 |
12 | 717a41002405 |
13 | 2c617758bc51 |
14 | 14499ac02645 |
15 | 92e55b4ddb2 |
hex | 4d2d3a69fc5 |
5303540555717 has 2 divisors, whose sum is σ = 5303540555718. Its totient is φ = 5303540555716.
The previous prime is 5303540555707. The next prime is 5303540555813. The reversal of 5303540555717 is 7175550453035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5270885897281 + 32654658436 = 2295841^2 + 180706^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303540555717 - 24 = 5303540555701 is a prime.
It is a super-2 number, since 2×53035405557172 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5303540555707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651770277858 + 2651770277859.
It is an arithmetic number, because the mean of its divisors is an integer number (2651770277859).
Almost surely, 25303540555717 is an apocalyptic number.
It is an amenable number.
5303540555717 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303540555717 is an equidigital number, since it uses as much as digits as its factorization.
5303540555717 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5512500, while the sum is 50.
The spelling of 5303540555717 in words is "five trillion, three hundred three billion, five hundred forty million, five hundred fifty-five thousand, seven hundred seventeen".
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