Search a number
-
+
5303541125345 = 59910910702441
BaseRepresentation
bin100110100101101001110…
…1011110101000011100001
3200210000100220021221220212
41031023103223311003201
51143343123012002340
615140225124143505
71055111456520221
oct115132353650341
920700326257825
105303541125345
11176524577a731
12717a41237b95
132c617772b2c8
1414499ad10081
1592e55c12a65
hex4d2d3af50e1

5303541125345 has 8 divisors (see below), whose sum is σ = 6364314159720. Its totient is φ = 4242789694080.

The previous prime is 5303541125339. The next prime is 5303541125383. The reversal of 5303541125345 is 5435211453035.

It can be written as a sum of positive squares in 4 ways, for example, as 1141871765056 + 4161669360289 = 1068584^2 + 2040017^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5303541125345 - 216 = 5303541059809 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4855676 + ... + 5846765.

It is an arithmetic number, because the mean of its divisors is an integer number (795539269965).

Almost surely, 25303541125345 is an apocalyptic number.

It is an amenable number.

5303541125345 is a deficient number, since it is larger than the sum of its proper divisors (1060773034375).

5303541125345 is a wasteful number, since it uses less digits than its factorization.

5303541125345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10801555.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 5303541125345 in words is "five trillion, three hundred three billion, five hundred forty-one million, one hundred twenty-five thousand, three hundred forty-five".

Divisors: 1 5 99109 495545 10702441 53512205 1060708225069 5303541125345