Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00100000011011111101 |
3 | 1212200221021220001020220 |
4 | 13231323210200123331 |
5 | 32142131130120041 |
6 | 1043350305531553 |
7 | 53213445565101 |
oct | 7557344403375 |
9 | 1780837801226 |
10 | 530354145021 |
11 | 194a160a7968 |
12 | 86952643bb9 |
13 | 3b0209ba92c |
14 | 1b9526d7901 |
15 | dbe08b3d66 |
hex | 7b7b9206fd |
530354145021 has 4 divisors (see below), whose sum is σ = 707138860032. Its totient is φ = 353569430012.
The previous prime is 530354144981. The next prime is 530354145047. The reversal of 530354145021 is 120541453035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530354145021 - 222 = 530349950717 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530354145521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88392357501 + ... + 88392357506.
It is an arithmetic number, because the mean of its divisors is an integer number (176784715008).
Almost surely, 2530354145021 is an apocalyptic number.
It is an amenable number.
530354145021 is a deficient number, since it is larger than the sum of its proper divisors (176784715011).
530354145021 is a wasteful number, since it uses less digits than its factorization.
530354145021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176784715010.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 530354145021 its reverse (120541453035), we get a palindrome (650895598056).
The spelling of 530354145021 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred forty-five thousand, twenty-one".
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