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530354145021 = 3176784715007
BaseRepresentation
bin1111011011110111001…
…00100000011011111101
31212200221021220001020220
413231323210200123331
532142131130120041
61043350305531553
753213445565101
oct7557344403375
91780837801226
10530354145021
11194a160a7968
1286952643bb9
133b0209ba92c
141b9526d7901
15dbe08b3d66
hex7b7b9206fd

530354145021 has 4 divisors (see below), whose sum is σ = 707138860032. Its totient is φ = 353569430012.

The previous prime is 530354144981. The next prime is 530354145047. The reversal of 530354145021 is 120541453035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530354145021 - 222 = 530349950717 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530354145521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88392357501 + ... + 88392357506.

It is an arithmetic number, because the mean of its divisors is an integer number (176784715008).

Almost surely, 2530354145021 is an apocalyptic number.

It is an amenable number.

530354145021 is a deficient number, since it is larger than the sum of its proper divisors (176784715011).

530354145021 is a wasteful number, since it uses less digits than its factorization.

530354145021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176784715010.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 530354145021 its reverse (120541453035), we get a palindrome (650895598056).

The spelling of 530354145021 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred forty-five thousand, twenty-one".

Divisors: 1 3 176784715007 530354145021