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5303653 = 6779159
BaseRepresentation
bin10100001110110101100101
3100222110020121
4110032311211
52324204103
6305401541
763036355
oct24166545
910873217
105303653
112aa2793
1219392b1
131139074
149c0b65
156eb6bd
hex50ed65

5303653 has 4 divisors (see below), whose sum is σ = 5382880. Its totient is φ = 5224428.

The previous prime is 5303651. The next prime is 5303659. The reversal of 5303653 is 3563035.

5303653 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5303653 - 21 = 5303651 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5303651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39513 + ... + 39646.

It is an arithmetic number, because the mean of its divisors is an integer number (1345720).

Almost surely, 25303653 is an apocalyptic number.

It is an amenable number.

5303653 is a deficient number, since it is larger than the sum of its proper divisors (79227).

5303653 is an equidigital number, since it uses as much as digits as its factorization.

5303653 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79226.

The product of its (nonzero) digits is 4050, while the sum is 25.

The square root of 5303653 is about 2302.9661308843. The cubic root of 5303653 is about 174.3913878733.

Adding to 5303653 its reverse (3563035), we get a palindrome (8866688).

The spelling of 5303653 in words is "five million, three hundred three thousand, six hundred fifty-three".

Divisors: 1 67 79159 5303653