Base | Representation |
---|---|
bin | 110001011001010111… |
… | …010010000011011011 |
3 | 12001220101000102110101 |
4 | 301121113102003123 |
5 | 1332110423224120 |
6 | 40210555200231 |
7 | 3555232032025 |
oct | 613127220333 |
9 | 161811012411 |
10 | 53038883035 |
11 | 20548080936 |
12 | a342746077 |
13 | 5003519578 |
14 | 27d2179015 |
15 | 15a656990a |
hex | c595d20db |
53038883035 has 4 divisors (see below), whose sum is σ = 63646659648. Its totient is φ = 42431106424.
The previous prime is 53038882997. The next prime is 53038883057.
53038883035 is nontrivially palindromic in base 10.
53038883035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53038883035 - 213 = 53038874843 is a prime.
It is a super-2 number, since 2×530388830352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303888299 + ... + 5303888308.
It is an arithmetic number, because the mean of its divisors is an integer number (15911664912).
Almost surely, 253038883035 is an apocalyptic number.
53038883035 is a deficient number, since it is larger than the sum of its proper divisors (10607776613).
53038883035 is a wasteful number, since it uses less digits than its factorization.
53038883035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10607776612.
The product of its (nonzero) digits is 1036800, while the sum is 46.
The spelling of 53038883035 in words is "fifty-three billion, thirty-eight million, eight hundred eighty-three thousand, thirty-five".
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