Base | Representation |
---|---|
bin | 110001011001011001… |
… | …100011110001011101 |
3 | 12001220102010202012112 |
4 | 301121121203301131 |
5 | 1332111101324101 |
6 | 40211020043405 |
7 | 3555240066122 |
oct | 613131436135 |
9 | 161812122175 |
10 | 53039479901 |
11 | 20548449311 |
12 | a342993565 |
13 | 5003698145 |
14 | 27d2292749 |
15 | 15a66366bb |
hex | c59663c5d |
53039479901 has 4 divisors (see below), whose sum is σ = 53044124832. Its totient is φ = 53034834972.
The previous prime is 53039479879. The next prime is 53039479937. The reversal of 53039479901 is 10997493035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53039479901 - 218 = 53039217757 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 53039479901.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53039479991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2305295 + ... + 2328188.
It is an arithmetic number, because the mean of its divisors is an integer number (13261031208).
Almost surely, 253039479901 is an apocalyptic number.
It is an amenable number.
53039479901 is a deficient number, since it is larger than the sum of its proper divisors (4644931).
53039479901 is a wasteful number, since it uses less digits than its factorization.
53039479901 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4644930.
The product of its (nonzero) digits is 918540, while the sum is 50.
The spelling of 53039479901 in words is "fifty-three billion, thirty-nine million, four hundred seventy-nine thousand, nine hundred one".
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