Base | Representation |
---|---|
bin | 1111011011111100010… |
… | …01110111001001111001 |
3 | 1212201001022110021220101 |
4 | 13231332021313021321 |
5 | 32142223224214313 |
6 | 1043354454555401 |
7 | 53214513202456 |
oct | 7557611671171 |
9 | 1781038407811 |
10 | 530397491833 |
11 | 194a38613a80 |
12 | 86965068b61 |
13 | 3b029986931 |
14 | 1b95837c82d |
15 | dbe45c75dd |
hex | 7b7e277279 |
530397491833 has 4 divisors (see below), whose sum is σ = 578615445648. Its totient is φ = 482179538020.
The previous prime is 530397491809. The next prime is 530397491867. The reversal of 530397491833 is 338194793035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530397491833 - 213 = 530397483641 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530397491033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24108976891 + ... + 24108976912.
It is an arithmetic number, because the mean of its divisors is an integer number (144653861412).
Almost surely, 2530397491833 is an apocalyptic number.
It is an amenable number.
530397491833 is a deficient number, since it is larger than the sum of its proper divisors (48217953815).
530397491833 is a wasteful number, since it uses less digits than its factorization.
530397491833 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48217953814.
The product of its (nonzero) digits is 7348320, while the sum is 55.
The spelling of 530397491833 in words is "five hundred thirty billion, three hundred ninety-seven million, four hundred ninety-one thousand, eight hundred thirty-three".
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