5304021433 has 4 divisors (see below), whose sum is σ = 5383186000. Its totient is φ = 5224856868.

The previous prime is 5304021419. The next prime is 5304021479. The reversal of 5304021433 is 3341204035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5304021433 - 2⁹ = 5304020921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5304021398 and 5304021407.

It is not an unprimeable number, because it can be changed into a prime (5304021413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39582183 + ... + 39582316.

It is an arithmetic number, because the mean of its divisors is an integer number (1345796500).

Almost surely, 2^5304021433 is an apocalyptic number.

It is an amenable number.

5304021433 is a deficient number, since it is larger than the sum of its proper divisors (79164567).

5304021433 is an equidigital number, since it uses as much as digits as its factorization.

5304021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79164566.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 5304021433 is about 72828.7129709155. The cubic root of 5304021433 is about 1743.9542597396.

Adding to 5304021433 its reverse (3341204035), we get a palindrome (8645225468).

The spelling of 5304021433 in words is "five billion, three hundred four million, twenty-one thousand, four hundred thirty-three".