Base | Representation |
---|---|
bin | 1111011011111100110… |
… | …11101000101011001001 |
3 | 1212201001122020000020022 |
4 | 13231332123220223021 |
5 | 32142230422313423 |
6 | 1043355142510225 |
7 | 53214600616412 |
oct | 7557633505311 |
9 | 1781048200208 |
10 | 530402151113 |
11 | 194a4020661a |
12 | 86966735375 |
13 | 3b02a9285c3 |
14 | 1b958c32809 |
15 | dbe4be7dc8 |
hex | 7b7e6e8ac9 |
530402151113 has 2 divisors, whose sum is σ = 530402151114. Its totient is φ = 530402151112.
The previous prime is 530402151089. The next prime is 530402151241. The reversal of 530402151113 is 311151204035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 309077066809 + 221325084304 = 555947^2 + 470452^2 .
It is a cyclic number.
It is not a de Polignac number, because 530402151113 - 26 = 530402151049 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (530402151313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265201075556 + 265201075557.
It is an arithmetic number, because the mean of its divisors is an integer number (265201075557).
Almost surely, 2530402151113 is an apocalyptic number.
It is an amenable number.
530402151113 is a deficient number, since it is larger than the sum of its proper divisors (1).
530402151113 is an equidigital number, since it uses as much as digits as its factorization.
530402151113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 530402151113 its reverse (311151204035), we get a palindrome (841553355148).
The spelling of 530402151113 in words is "five hundred thirty billion, four hundred two million, one hundred fifty-one thousand, one hundred thirteen".
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