Base | Representation |
---|---|
bin | 1111011011111100110… |
… | …11101000101101001001 |
3 | 1212201001122020000102001 |
4 | 13231332123220231021 |
5 | 32142230422314431 |
6 | 1043355142511001 |
7 | 53214600616654 |
oct | 7557633505511 |
9 | 1781048200361 |
10 | 530402151241 |
11 | 194a40206726 |
12 | 86966735461 |
13 | 3b02a928691 |
14 | 1b958c3289b |
15 | dbe4be7e61 |
hex | 7b7e6e8b49 |
530402151241 has 2 divisors, whose sum is σ = 530402151242. Its totient is φ = 530402151240.
The previous prime is 530402151113. The next prime is 530402151271. The reversal of 530402151241 is 142151204035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 280242125641 + 250160025600 = 529379^2 + 500160^2 .
It is a cyclic number.
It is not a de Polignac number, because 530402151241 - 27 = 530402151113 is a prime.
It is not a weakly prime, because it can be changed into another prime (530402151271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265201075620 + 265201075621.
It is an arithmetic number, because the mean of its divisors is an integer number (265201075621).
Almost surely, 2530402151241 is an apocalyptic number.
It is an amenable number.
530402151241 is a deficient number, since it is larger than the sum of its proper divisors (1).
530402151241 is an equidigital number, since it uses as much as digits as its factorization.
530402151241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 530402151241 its reverse (142151204035), we get a palindrome (672553355276).
The spelling of 530402151241 in words is "five hundred thirty billion, four hundred two million, one hundred fifty-one thousand, two hundred forty-one".
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