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530402304983 is a prime number
BaseRepresentation
bin1111011011111100111…
…00001110001111010111
31212201001122111211022012
413231332130032033113
532142230442224413
61043355150054435
753214602130125
oct7557634161727
91781048454265
10530402304983
11194a40301191
12869667aa41b
133b02a980655
141b958c72915
15dbe4c287a8
hex7b7e70e3d7

530402304983 has 2 divisors, whose sum is σ = 530402304984. Its totient is φ = 530402304982.

The previous prime is 530402304977. The next prime is 530402304997. The reversal of 530402304983 is 389403204035.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 530402304983 - 222 = 530398110679 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 530402304983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530402304683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265201152491 + 265201152492.

It is an arithmetic number, because the mean of its divisors is an integer number (265201152492).

Almost surely, 2530402304983 is an apocalyptic number.

530402304983 is a deficient number, since it is larger than the sum of its proper divisors (1).

530402304983 is an equidigital number, since it uses as much as digits as its factorization.

530402304983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 530402304983 in words is "five hundred thirty billion, four hundred two million, three hundred four thousand, nine hundred eighty-three".