Search a number
-
+
530402445443 = 1340800188111
BaseRepresentation
bin1111011011111100111…
…00110000100010000011
31212201001122202221222102
413231332130300202003
532142231011223233
61043355153101015
753214603253463
oct7557634604203
91781048687872
10530402445443
11194a40397772
128696685776b
133b02a9cc570
141b958cabba3
15dbe4c551e8
hex7b7e730883

530402445443 has 4 divisors (see below), whose sum is σ = 571202633568. Its totient is φ = 489602257320.

The previous prime is 530402445437. The next prime is 530402445487. The reversal of 530402445443 is 344544204035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530402445443 - 226 = 530335336579 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530402445397 and 530402445406.

It is not an unprimeable number, because it can be changed into a prime (530402445043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20400094043 + ... + 20400094068.

It is an arithmetic number, because the mean of its divisors is an integer number (142800658392).

Almost surely, 2530402445443 is an apocalyptic number.

530402445443 is a deficient number, since it is larger than the sum of its proper divisors (40800188125).

530402445443 is a wasteful number, since it uses less digits than its factorization.

530402445443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40800188124.

The product of its (nonzero) digits is 460800, while the sum is 38.

Adding to 530402445443 its reverse (344544204035), we get a palindrome (874946649478).

The spelling of 530402445443 in words is "five hundred thirty billion, four hundred two million, four hundred forty-five thousand, four hundred forty-three".

Divisors: 1 13 40800188111 530402445443