Base | Representation |
---|---|
bin | 1111011011111101000… |
… | …11010001110011000011 |
3 | 1212201001202222210110011 |
4 | 13231332203101303003 |
5 | 32142231430421223 |
6 | 1043355253445351 |
7 | 53214623632363 |
oct | 7557643216303 |
9 | 1781052883404 |
10 | 530404154563 |
11 | 194a41354868 |
12 | 86967340857 |
13 | 3b02b17a48a |
14 | 1b9591d49a3 |
15 | dbe4e9180d |
hex | 7b7e8d1cc3 |
530404154563 has 2 divisors, whose sum is σ = 530404154564. Its totient is φ = 530404154562.
The previous prime is 530404154513. The next prime is 530404154569. The reversal of 530404154563 is 365451404035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530404154563 - 217 = 530404023491 is a prime.
It is not a weakly prime, because it can be changed into another prime (530404154569) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265202077281 + 265202077282.
It is an arithmetic number, because the mean of its divisors is an integer number (265202077282).
Almost surely, 2530404154563 is an apocalyptic number.
530404154563 is a deficient number, since it is larger than the sum of its proper divisors (1).
530404154563 is an equidigital number, since it uses as much as digits as its factorization.
530404154563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 530404154563 its reverse (365451404035), we get a palindrome (895855558598).
The spelling of 530404154563 in words is "five hundred thirty billion, four hundred four million, one hundred fifty-four thousand, five hundred sixty-three".
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