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530404414411 = 598989905329
BaseRepresentation
bin1111011011111101001…
…00010001001111001011
31212201001210110222220011
413231332210101033023
532142232012230121
61043355303212351
753214626064064
oct7557644211713
91781053428804
10530404414411
11194a41512013
12869674470b7
133b02b23b831
141b95926156b
15dbe4ee37e1
hex7b7e9113cb

530404414411 has 4 divisors (see below), whose sum is σ = 539394319800. Its totient is φ = 521414509024.

The previous prime is 530404414361. The next prime is 530404414417. The reversal of 530404414411 is 114414404035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530404414411 - 29 = 530404413899 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (530404414417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4494952606 + ... + 4494952723.

It is an arithmetic number, because the mean of its divisors is an integer number (134848579950).

Almost surely, 2530404414411 is an apocalyptic number.

530404414411 is a deficient number, since it is larger than the sum of its proper divisors (8989905389).

530404414411 is an equidigital number, since it uses as much as digits as its factorization.

530404414411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8989905388.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 530404414411 its reverse (114414404035), we get a palindrome (644818818446).

The spelling of 530404414411 in words is "five hundred thirty billion, four hundred four million, four hundred fourteen thousand, four hundred eleven".

Divisors: 1 59 8989905329 530404414411